Sindh Text Board Jamshoro
Class XI / HSC-ΙI丨Chapter # 2丨Problem
VECTORS
Problem 2.6
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Tuesday, November 10, 2020
Monday, November 9, 2020
Motion under Gravity
MOTION UNDER GRAVITY
When a body drop from a certain height, it moves towards the
ground and its velocity increases continuously till it strike the ground and
then body get some acceleration which is called acceleration due to gravity and
it is define as follow
“The
acceleration produces in a free falling body due to force of gravity is called
acceleration due to gravity”.
Acceleration due to gravity is denoted by ‘g’ and its value is 9.8 m/s2.
EQUATIONS OF MOTION
DURING MOTION UNDER GRAVITY
Sunday, November 8, 2020
Difference b/w velocity and acceleration
DIFFERENTIATE B/W VELOCITY
AND ACCELERATION
|
VELOCITY |
ACCELERATION |
|
v
Velocity of the body is the rate of
change of displacement. v
Its unit is ms-1. v
It is zero when the body at rest. |
v
Acceleration of a body is the rate
of change of velocity. v
Its unit is ms-2. v
It is zero for an object at rest or
on uniform motion. |
DIFFERENTIATE B/W SPEED AND VELOCITY
DIFFERENTIATE B/W SPEED AND VELOCITY
|
SPEED |
VELOCITY |
|
v
Speed of the body is the rate of
change of distance. v
Speed does not tell us anything
about the direction of its motion. v
It is scalar quantity. v
It’s unit is ms-1. |
v
Velocity of the body is the rate of
change of displacement. v
Velocity of the body tell us the
direction on which the body is moving. v
It is vector quantity. v
It’s unit is ms-1. |
Tuesday, November 3, 2020
Chapter 9 Problems, Physics, Problem # 9.6 (The length of the handle of screw jack is 40 cm and its pitch is 4 mm. How much load can be lifted by applying a force of 5N on the handle)
Sindh Text Board Jamshoro
Class X / SSC-ΙI丨Chapter # 9丨Problems
Problem #9.6
The length
of the handle of screw jack is 40 cm and its pitch is 4 mm. How much load can
be lifted by applying a force of 5N on the handle.
Chapter 9 Problems, Physics, Problem # 9.5 (A load of 21000 N Placed on the top of a screw jack of is lifted by a force of 300 N. If the length of the Tommy-bar is 35 cm and the pitch of the screw is 2.5 mm, find its mechanical advantage and efficiency.)
Sindh Text Board Jamshoro
Class X / SSC-ΙI丨Chapter # 9丨Problems
Problem
#9.5
A
load of 21000 N Placed on the top of a screw jack of is lifted by a force of
300 N. If the length of the Tommy-bar is 35 cm and the pitch of the screw is
2.5 mm, find its mechanical advantage and efficiency.
Chapter 9 Problems, Physics, Problem # 9.4 (An effort of 100N, applied to a pulley system is able lift a load of 400N through a vertical height of 1 m. To do this, the effort moves a distance of 8 m. Calculate: (a) Mechanical Advantage of the pulley. (b) The efficiency.)
Sindh Text Board Jamshoro
Class X / SSC-ΙI丨Chapter # 9丨Problems
Problem
#9.4
An effort of 100N, applied to a pulley system is able lift a load of 400N through a vertical height of 1 m. To do this, the effort moves a distance of 8 m. Calculate:
(a) Mechanical Advantage of the pulley.
(b) The efficiency.
Chapter 9 Problems, Physics, Problem # 9.3 (An object of mass 100 kg is raised 2m above the ground using an inclined plane of length 10m. Calculate the effort applied parallel to the inclined plane.)
Sindh Text Board Jamshoro
Class X / SSC-ΙI丨Chapter # 9丨Problems
Problem
#9.3
An object
of mass 100 kg is raised 2m above the ground using an inclined plane of length
10m. Calculate the effort applied parallel to the inclined plane.
Chapter 9 Problems, Physics, Problem # 9.2 ,(The ratio between the length of the arms of lever is 4:1. How much force be applied to the longer arm so that a load of 20N suspended at the shorter arm can be balanced.)
Sindh Text Board Jamshoro
Class X / SSC-ΙI丨Chapter # 9丨Problems
Problem
#9.2
The ratio
between the length of the arms of lever is 4:1. How much force be applied to
the longer arm so that a load of 20N suspended at the shorter arm can be
balanced.
Chapter 9 Problems, Physics, Problem #9.1 (An effort of 160 N, applied to a pulley system is able to lift a load of 750 N through a vertical height 0f 1.2 m. To do this, the effort moves a distance of 7.2 m. Calculate: (a) The mechanical advantage of the pulley system. (b) The efficiency.)
Sindh Text Board Jamshoro
Class X / SSC-ΙI丨Chapter # 9丨Problems
Problem #9.1
An effort of 160 N, applied to a pulley system is able to lift a load of 750 N through a vertical height 0f 1.2 m. To do this, the effort moves a distance of 7.2 m. Calculate:
(a) The mechanical advantage of the pulley system.
(b) The efficiency.
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